Hello,
I have purchased a new SSD to replace my existing HDD as my main (C: ) drive on my computer. I intend to re-install windows so its got a fresh copy to run as fast as possible. To avoid total failier I was intending to un-plug my exising HD (C: ) just incase something goes really wrong so I have a copy to quickly.
I assume when I plug in the new SSD without the exisitng plugged it will allocate it as the new C: drive and I can install windows on that. The question I have is when I plug other HD back in (which was formally C: ) will this cause a conflict??? or will it simply allocate a new drive letter and work fine?
As before I dont want to reformat prior to install to make sure that if worse comes to worst and the new SSD dont install or is faulty then I can simply plug back in and works as usual. I am just concerned that when I plug in to reformat its likely to cause a conflict as both will have windows on and formally allocated as C:
I hope this makes sence and thank you in advance for any helpful advice.
I have purchased a new SSD to replace my existing HDD as my main (C: ) drive on my computer. I intend to re-install windows so its got a fresh copy to run as fast as possible. To avoid total failier I was intending to un-plug my exising HD (C: ) just incase something goes really wrong so I have a copy to quickly.
I assume when I plug in the new SSD without the exisitng plugged it will allocate it as the new C: drive and I can install windows on that. The question I have is when I plug other HD back in (which was formally C: ) will this cause a conflict??? or will it simply allocate a new drive letter and work fine?
As before I dont want to reformat prior to install to make sure that if worse comes to worst and the new SSD dont install or is faulty then I can simply plug back in and works as usual. I am just concerned that when I plug in to reformat its likely to cause a conflict as both will have windows on and formally allocated as C:
I hope this makes sence and thank you in advance for any helpful advice.