I have a PC with 8GB of DDR3 RAM (2x4GB). I bought two more sticks of RAM (2x4GB) with very different specs, and I'd like to have them running alongside one another to create 16GB, if possible - I just don't want to fry any components.
Set 1: 1333 MHz / 9-9-9-24 / 1.5v
Set 2: 2133 MHz / 11-11-11-30 / 1.6v
My mobo only supports up to 1333 MHz, so I have to underclock Set 2 (which should happen by default). I don't think that the timings and voltage are adjusted along with the speed though - please correct me if I am wrong. It's also worth noting that my mobo supports two channels of RAM.
I want to get into the BIOS and set the timings and voltage manually, but I don't know what values to set the timings and voltage to for the best compatibility, and I didn't know if there was some way of calculating that information.
What values would work best, do you think? Can you explain why? Is this a terrible, terrible idea?
(Side note - I bought the new RAM with a friend who only needed 8GB more to match what he already had, so I got a steep discount overall but that is the reason why the specs of the new RAM far exceed those of my existing set.)
Thank you!
Set 1: 1333 MHz / 9-9-9-24 / 1.5v
Set 2: 2133 MHz / 11-11-11-30 / 1.6v
My mobo only supports up to 1333 MHz, so I have to underclock Set 2 (which should happen by default). I don't think that the timings and voltage are adjusted along with the speed though - please correct me if I am wrong. It's also worth noting that my mobo supports two channels of RAM.
I want to get into the BIOS and set the timings and voltage manually, but I don't know what values to set the timings and voltage to for the best compatibility, and I didn't know if there was some way of calculating that information.
What values would work best, do you think? Can you explain why? Is this a terrible, terrible idea?
(Side note - I bought the new RAM with a friend who only needed 8GB more to match what he already had, so I got a steep discount overall but that is the reason why the specs of the new RAM far exceed those of my existing set.)
Thank you!