Over current detected in USB device!! System shutdown in 15 seconds to protect motherboard !!

Steven77

Commendable
Jan 18, 2017
1
0
1,510
Hello,
I have been getting the error message " over current detected in USB device!! System shutdown in 15 seconds to protect motherboard !
I have removed all USB wires from my case to my motherboard. I have inspected and removed everything plugged into the USB ports. No USB port looks damaged. Please help
 
Solution
It is very likely that you have a fried/damaged TVS (ESD protection) diode on the USB VBUS line. USB ports usually have TVS (Transient voltage suppressor) devices on all data and VBUS wires. Mainboards usually have some means to detect if the VBUS voltage is up (if overcurrent occurs, the VBUS will be down).
In most cases the port power delivery is protected by "resettable fuse", or "polyfuse". So the "overcurrent" message will appear if the polyfuse failed to self reset. You need to determine if the overcurrent is real (broken TVS), or fake (broken polyfuse). One way to determine it is to measure the power consumption of your system when it is in standby mode (not powered up, but connected to AC mains), using some power meter like...

Ali_200

Commendable
Jan 19, 2017
13
0
1,520
It is very likely that you have a fried/damaged TVS (ESD protection) diode on the USB VBUS line. USB ports usually have TVS (Transient voltage suppressor) devices on all data and VBUS wires. Mainboards usually have some means to detect if the VBUS voltage is up (if overcurrent occurs, the VBUS will be down).
In most cases the port power delivery is protected by "resettable fuse", or "polyfuse". So the "overcurrent" message will appear if the polyfuse failed to self reset. You need to determine if the overcurrent is real (broken TVS), or fake (broken polyfuse). One way to determine it is to measure the power consumption of your system when it is in standby mode (not powered up, but connected to AC mains), using some power meter like Kill-A-Watt. If the standby power is above 2W, then there is some partial physical short (because if there is a real short on VBUS, this will short +5VSB standby rail, and computer will die completely).
 
Solution