slingsrat :
bmockeg :
Bro, you realize it is DOUBLE DATA RATE (DDR) all those numbers are doubled for effective rate. 2133 for the 1st three and the XMP profile will be 3000. As has already been stated, you don't know what you are talking about. If You don't believe us, start your own thread. You can actually just search for the many threads already explaining this. If You use CPU-Z it will also read 1066 or 1500. Actual speeds are DOUBLE the data rate of 1066 or 1500 which is 2133 or 3000.
Actual speeds are double when you use two sticks in dual channel configuration. Tell me why they even invented dual channel if one stick can run as fast as two? Use your brain.
Each memory channel is an independent system. For a computer with a single system bus, the theoretical peak memory bandwidth is the number of memory channels multiplied by the configured bandwidth of a single channel.
This is an incredibly simplistic view of memory architecture, but it is a sufficient one for our purposes.
In most cases the IO clock on each channel will be the same. For example, DDR4-2400 has an IO clock of 1,200Mhz.
Peak bandwidth with one channel is 1.2E9 * 64 bits/transfer * 2 transfers per clock = 153.6 gigabits per second = 19.2 gigabytes per second
With two channels, the bandwidth doubles to 38.4 gigabytes per second. The IO clock is still 1,200Mhz and the DIMMs are still DDR4-2400.
With four channels, the bandwidth is 76.8 gigabytes per second. The IO clock is still 1,200Mhz and the DIMMs are still DDR4-2400.
This assumes that all channels are fully rank balanced which need not always be the case.