The other day whilst doing nothing important at school, I did a few quick doodles of a new water block design I had in mind, it probably won't work, but nonetheless I did a few quick sketches on my computer when I got home to see what you guys thought...
<A HREF="http://www.btinternet.com/~karl28/design1pic1.jpg" target="_new">http://www.btinternet.com/~karl28/design1pic1.jpg</A>
I haven't had time to add the dimensions onto the drawing, but I hope you can see the general idea. The block is 50mm x 90mm, and should in theory fit most Socket A boards, as it only requires 15mm either side of the processor. The block should be long enough to incorporate two 40mm pelts, which can just be seen.
The reason I designed a block with 2 pelts is because of the increasing amount of heat that Athlon-T processors are giving out, and as a result, most pelts are no longer able to cool Thunderbirds to any significant level, if at all.
Here's a quick pre-rendered view of the water block, in which you should be able to see the 4 cross-drilled channels, and the drilled hole for the thermistor...
<A HREF="http://www.btinternet.com/~karl28/enhancedview1.jpg" target="_new">http://www.btinternet.com/~karl28/enhancedview1.jpg</A>
Time for some quick Math;
Heat Production = CPU Spec Watts * (New speed/Spec speed) * (New Volts/Spec Volts)²
Athlon 1200 = 72 * (1733/1200) * (1.85/1.75)²
Athlon @ 1733MHz = 116 watts
dTload = (1 - (heat load/max cooling power)) * max temp difference
dTload = (1-(116/(172/2))*69 = 46°C
Th = Tamb + (C/W)(Pin + Qc)
Th = 20°C + (0.0.25 C/W)(172 + 172 + 116 Watts)
Th = 20C + 11.5°C= 31.5°C
Tc = Th - dT
Tc = 31.5°C - 46°C = <b><font color=red>-14.5°C</font color=red></b>
Under full load, the maximum heat the processor can dissipate is 116W, and in theory, this limit will never be reached in its full extent, however if it was to be reached, the processor should still be kept at a constant <b><font color=red>-14.5°C</font color=red></b>, as long as there is no heat loss from the cold-plate into the case, which will of course happen to a small degree. I don't know how much heat a processor dissipates at idle, nor how to work it out, but at a guess I expect to see temperatures as low as <b><font color=red>-40°C</font color=red></b>.
So, what do you people think of my design, and it's possible merits and drawback? Any opinions or comments would be greatly appreciated.
Kind regards in advance,
Karl Brown
<A HREF="mailto: karlbrown1@hotmail.com "> karlbrown1@hotmail.com </A>
<A HREF="http://www.btinternet.com/~karl28/design1pic1.jpg" target="_new">http://www.btinternet.com/~karl28/design1pic1.jpg</A>
I haven't had time to add the dimensions onto the drawing, but I hope you can see the general idea. The block is 50mm x 90mm, and should in theory fit most Socket A boards, as it only requires 15mm either side of the processor. The block should be long enough to incorporate two 40mm pelts, which can just be seen.
The reason I designed a block with 2 pelts is because of the increasing amount of heat that Athlon-T processors are giving out, and as a result, most pelts are no longer able to cool Thunderbirds to any significant level, if at all.
Here's a quick pre-rendered view of the water block, in which you should be able to see the 4 cross-drilled channels, and the drilled hole for the thermistor...
<A HREF="http://www.btinternet.com/~karl28/enhancedview1.jpg" target="_new">http://www.btinternet.com/~karl28/enhancedview1.jpg</A>
Time for some quick Math;
Heat Production = CPU Spec Watts * (New speed/Spec speed) * (New Volts/Spec Volts)²
Athlon 1200 = 72 * (1733/1200) * (1.85/1.75)²
Athlon @ 1733MHz = 116 watts
dTload = (1 - (heat load/max cooling power)) * max temp difference
dTload = (1-(116/(172/2))*69 = 46°C
Th = Tamb + (C/W)(Pin + Qc)
Th = 20°C + (0.0.25 C/W)(172 + 172 + 116 Watts)
Th = 20C + 11.5°C= 31.5°C
Tc = Th - dT
Tc = 31.5°C - 46°C = <b><font color=red>-14.5°C</font color=red></b>
Under full load, the maximum heat the processor can dissipate is 116W, and in theory, this limit will never be reached in its full extent, however if it was to be reached, the processor should still be kept at a constant <b><font color=red>-14.5°C</font color=red></b>, as long as there is no heat loss from the cold-plate into the case, which will of course happen to a small degree. I don't know how much heat a processor dissipates at idle, nor how to work it out, but at a guess I expect to see temperatures as low as <b><font color=red>-40°C</font color=red></b>.
So, what do you people think of my design, and it's possible merits and drawback? Any opinions or comments would be greatly appreciated.
Kind regards in advance,
Karl Brown
<A HREF="mailto: karlbrown1@hotmail.com "> karlbrown1@hotmail.com </A>