2 weeks ago my motherboard (ASUS P4PE AGP-4x) and my video card (Leadtek 6800GT AGP-8X) was broken.
I'm happy with my RAM (2x512MB DDR400) and CPU (P4 3.06GHz HT 478pin) so I've replaced my old motherboard with a ASUS P4V800D-X (based on VIA PT880Ultra and VIA 8237R).
This new mobo support my old CPU and RAM and has one AGP-8x slot and one PCI-E 16x slot but running ad 4x speed max.
Now I need to buy a new video card. I thought a card based on Nvidia 7900GT GPU.
My question is: a video card based on PCI-E 16x can work at lower speed (PCI-E 4x) ? An AGP-8X card can work in a 8x and 4x AGP slot and (perhaps) 1x AGP slot. Is it the same for PCI-E ?
Yes I know that PCI-E 4x is slower than PCI-E 16x, but PCI-E 4x is equal to AGP-8x and for now I'm satisfied.... In the future, if I'll change CPU and mobo with a real PCI-E 16x I'll have a video card 'PCI-E 16x ready'.....
2 weeks ago my motherboard (ASUS P4PE AGP-4x) and my video card (Leadtek 6800GT AGP-8X) was broken.
I'm happy with my RAM (2x512MB DDR400) and CPU (P4 3.06GHz HT 478pin) so I've replaced my old motherboard with a ASUS P4V800D-X (based on VIA PT880Ultra and VIA 8237R).
This new mobo support my old CPU and RAM and has one AGP-8x slot and one PCI-E 16x slot but running ad 4x speed max.
Now I need to buy a new video card. I thought a card based on Nvidia 7900GT GPU.
My question is: a video card based on PCI-E 16x can work at lower speed (PCI-E 4x) ? An AGP-8X card can work in a 8x and 4x AGP slot and (perhaps) 1x AGP slot. Is it the same for PCI-E ?
Yes I know that PCI-E 4x is slower than PCI-E 16x, but PCI-E 4x is equal to AGP-8x and for now I'm satisfied.... In the future, if I'll change CPU and mobo with a real PCI-E 16x I'll have a video card 'PCI-E 16x ready'.....
Thanks in advance...
You're asking too many question for nothing..
Just put the PCI-e video card in the ONLY PCI-e slot that will accept it and have fun.
You are about to answer a thread that has been inactive for more than 6 months. If you still wish to proceed, please ensure that your posting is original and does not duplicate or overlap any prior responses to this thread.