Question about E6600, P5B Deluxe with 4x512 667 Ram
aretas
Here's my new machine:
Intel Core 2 Duo E6600
Arctic Cooling Freezer 7 Pro (Intel LGA775)
ASUS P5B Deluxe P965 M/B
Corsair TWIN2X10245400C4 x 2
WD 3200YS
Leadtek Winfast PX7900GS
Asus 16X DVDROM
Pioneer DVR111
Enermax EG495PVE SFMA
Originally I wanted to buy the 2x1G one, but it seemed that the 2x1G one is out of stock everywhere, so I was forced to change to 2 pairs of 2x512 one.
I do not plan to increase my ram past the 2G mark within one or two years.
And I want to overclock my E6600 to 333x9 to get the 1:1 FSB:DRAM.
So in this case will there be any noticeable differences on performance between the 2x1G and 4x512?
Thanks a lot.
Intel Core 2 Duo E6600
Arctic Cooling Freezer 7 Pro (Intel LGA775)
ASUS P5B Deluxe P965 M/B
Corsair TWIN2X10245400C4 x 2
WD 3200YS
Leadtek Winfast PX7900GS
Asus 16X DVDROM
Pioneer DVR111
Enermax EG495PVE SFMA
Originally I wanted to buy the 2x1G one, but it seemed that the 2x1G one is out of stock everywhere, so I was forced to change to 2 pairs of 2x512 one.
I do not plan to increase my ram past the 2G mark within one or two years.
And I want to overclock my E6600 to 333x9 to get the 1:1 FSB:DRAM.
So in this case will there be any noticeable differences on performance between the 2x1G and 4x512?
Thanks a lot.
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More about question e6600 deluxe 4x512

The way I understood it, if you clocked your fsb to 333 that would only be 1:2 if you have 4 sticks of ram
333 is the DDRII's true speed, time 2, double data rate
667, per stick so you will need an fsb 666 to hit 1:1 with four of those, the 2X1 gb stick would have been much better. Maybe I'm wrong, but the reason you need to match fsb 1600 two two sticks of ddr 800 is because it has to adress each stick, so 3.2 ghz fsb for 4 sticks of ddr II 800. 
Quote:The way I understood it, if you clocked your fsb to 333 that would only be 1:2 if you have 4 sticks of ram
333 is the DDRII's true speed, time 2, double data rate
667, per stick so you will need an fsb 666 to hit 1:1 with four of those, the 2X1 gb stick would have been much better. Maybe I'm wrong, but the reason you need to match fsb 1600 two two sticks of ddr 800 is because it has to adress each stick, so 3.2 ghz fsb for 4 sticks of ddr II 800.
Wrong, with a 1333 FSB (333MHz) and DDR2 667 memory you get a 1:1 divider. 
did you even read what I wrote?
yeah, with 2 sticks, with 4 you get 1:2 because you have to adress TWICE AS MANY STICKS. could be wrong, but if I am someone who actually knows something can correct my assumption and explain why. It could be that since 2 sticks run in one channel and the other 2 in the other channel in an interleave, the 1333 fsb equals 1:1. Think about it, why does 667 ram need a 1333 fsb for 1:1 instead of a 667 fsb. Because you double the speed, since it adresses either 2 channels, or the two physical sticks. That is the only thing I am unsure of, but either way your post was moronic. 
Quote:did you even read what I wrote?
Yes.Quote:yeah, with 2 sticks, with 4 you get 1:2 because you have to adress TWICE AS MANY STICKS. could be wrong, but if I am someone who actually knows something can correct my assumption and explain why. It could be that since 2 sticks run in one channel and the other 2 in the other channel in an interleave, the 1333 fsb equals 1:1. Think about it, why does 667 ram need a 1333 fsb for 1:1 instead of a 667 fsb. Because you double the speed, since it adresses either 2 channels, or the two physical sticks. That is the only thing I am unsure of, but either way your post was moronic.
moronic, sure. It's obvious you don't know what you're talking about.
We are talking about the divider here. DDR2 667 memory works at a 1:1 divider with a 1333 FSB. Period.
Now if you really know what you're talking about, you would know too that the 1:1 figure it's for the real clocks, not for the effective rate, so a 1:1 divider in this case means 333 MHZ FSB (1333) and 333 MHZ RAM (667), one is quad pumped and the other works at double data rate.
Same applies for a 266 MHZ FSB (1066) and 266 MHZ RAM (533), 1:1.
That is using the memory at 64 or 128 bits (dual channel).
The Double Data Rate has nothing to do with the Dual Channel memory architecture. 
ok, I'm getting two people saying the number of sticks doesn't matter.
I know the fsb of a conroe/allendale is quad pumped.
I know that a stick of DDR 667 is only 667 effective, it's true speed is 333. So, when we match an fsb of 1333 to ddr 667 to get that 1:1 we get a one to one after multiplying the 667 by 2
1333 equals 667 times 2,
why are we multiplying the effective ram speed by two?
That is what I have been getting at, if anyone can explain it, that would be great. I always thought it was because you are using 2 sticks in a dual channel configuration.\
http://forums.nvidia.com/lofiversion/index.php?t17802.html
^^^^I see shit like this all the time^^^^^ 
we're not multiplying the ram by 2.. since conroe's are all quad pumped to get the effective 1333 fsb we're taking the cpu mhz speed. which would be 333 and multiplying by 4 which equals your 1333 FSB. it just so happens that because the FSB:ram ratio is 1:1 your fsb and your memory speed are exactly the same. but your effective fsb is derived from the cpu speed x4. hope that helps..

He doesn't understand the fact that the divider we're talking about it's hardware implemented in the Memory Controller Hub. And it is based on the real clocks only (the divider)!!
Heck! He's mixing the command rate with the dual channel arch and DDR double data rate... He seriously needs to get his facts right.
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