Archived from groups: microsoft.public.win2000.general (More info?)
Using explorer to get to 'my documents' folder is always a laborious.
When I use the default link 'my documents' I get to the right place, but now
explorer looks different. I want it to show up with the two halves left part
for folders and the right part for subfolders and files, like it does when I
start explorer with its own icon.
I have compared all properties of the two, but they seem identical.
How can I achieve explorer being displayed as I have default AND getting to
the right folder with one click?
I already have an explorer desktop shortcut to the root of C:
properties:
target: C:\WINNT\explorer.scf
start in: %HOMEDRIVE%%HOMEPATH%
so I thought, if I make another one with
start in: C:\Documents and Settings\Administrator\Mijn documenten
but that doesn't work...
Archived from groups: microsoft.public.win2000.general (More info?)
"Crouchie1998" <crouchie1998@spamcop.net> schreef in bericht
news:ev6dIXfRFHA.3704@TK2MSFTNGP12.phx.gbl...
> I think your target should be:
>
> '%SystemRoot%\explorer.exe' an not 'C:\WINNT\explorer.scf'
>
> Surely, the 'scf' is for the icon (link) only, wheras you are linking to
> that link icon.
>
At first I thought you misunderstood my question, but I decided to try it
anyway. Problem solved! It's magic, however I haven't a clue how it works...
And e.g. when I examine the properties of the default Windows "My documents"
link, there don't seem to be these parameters at all.
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