My Q6600 requires less voltage at 100%?

bretterzsp

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Aug 21, 2008
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I have my Q6600 OC to 3.0 Ghz at 1.29 VCore, i have 2 questions: how do i determine my cpu VID, and why the hell does my Core voltage go down from 1.248 on idle to 1.184 on prime95 full load?? I am using CPU-Z to determine my VCore.
 

bretterzsp

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Aug 21, 2008
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Actually it my VCore goes down when my multiplier goes from 6x to 9x if i have it set to 1.29 Vcore in Bios and CPU-Z shows 1.184 does that mean my VDroop is around .01?
 
CPU-Z will tell you your VID. Take a look at the info shown on the CPU-Z screen.

Also, what you're seeing in regards to the VCore drop is called VDroop.

If your VCore goes from 1.29 to 1.184 that's more like a 0.106 change, rather than a 0.01 like you asked.

Also, if your multiplier goes from 9x to 6x, then you still have some of the power saving feature implemented in your BIOS. Due to that, as the CPU is cycled down, your BIOS may also be changing your VCore to reduce heat/energy.

This isn't always good when you OverClock as it can cause some instability when you're jumping back to 9x. If it runs fine for you, don't worry. If you have instability problems with your OC, then worry about it.
 

Lupiron

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You can determine your VID using Core Temp, or Real Temp.

CPUz only lists the current voltage to the cores. That is different from VID, as VID is a set factor at the factory.

--Lupi
 

Lupiron

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hey, at least i is under 1.3000!

You will need around 1.41-1.42 volts while loaded to be stable at 3.6 ghz or there abouts.

because of the huge Vdrop and droop you have, you will need to set the processor voltage way high in the bios to get that lowered value when testing.

--Lupi