TV set Ratios ( 16:9 / 4:3 )

Archived from groups: alt.video.digital-tv,alt.video.fullscreen,alt.video.tv-sets,rec.arts.video.production (More info?)

Hi,does anyone know what size 16:9 TV i would have to get, that when in 4:3
mode would give a 32 inch picture ? (IE,with black borders at the sides)
I worked it out to be about 42" but i'm not sure of the exact formula.
I may get a 16:9 TV soon to replace my current 32" 4:3 set,and i want to get
one big enough so that when watching 4:3 programmes,it isnt any smaller than
the 32" i have now.
Hope that question makes sense.!!! If anyone can answer that i would
appreciate it.

thanks

Archived from groups: alt.video.digital-tv,alt.video.fullscreen,alt.video.tv-sets,rec.arts.video.production (More info?)

"me" <me@here.com> writes:

> Hi,does anyone know what size 16:9 TV i would have to get, that when in 4:3
> mode would give a 32 inch picture ? (IE,with black borders at the sides)
> I worked it out to be about 42" but i'm not sure of the exact formula.
> I may get a 16:9 TV soon to replace my current 32" 4:3 set,and i want to get
> one big enough so that when watching 4:3 programmes,it isnt any smaller than
> the 32" i have now.
> Hope that question makes sense.!!! If anyone can answer that i would
> appreciate it.
>
> thanks
>
>

What you are requesting is an identical ratio, i.e.,

16/9 X
- = -
4/3 32

X = 32 * 16/9
-
4/3

X = 42.58

--

Archived from groups: alt.video.digital-tv,alt.video.fullscreen,alt.video.tv-sets,rec.arts.video.production (More info?)

"me" <me@here.com> wrote in message news:U7xSd.991$755.467@lakeread05...
> Hi,does anyone know what size 16:9 TV i would have to get, that when in
> 4:3
> mode would give a 32 inch picture ? (IE,with black borders at the sides)
> I worked it out to be about 42" but i'm not sure of the exact formula.
> I may get a 16:9 TV soon to replace my current 32" 4:3 set,and i want to
> get
> one big enough so that when watching 4:3 programmes,it isnt any smaller
> than
> the 32" i have now.
> Hope that question makes sense.!!! If anyone can answer that i would
> appreciate it.
>
> thanks
>
>

32" @ 4:3 " Diag 32"; width 25.6"; height 19.2"

42" @ 16:9 Diag 42"; width 36.6"; height 20.6" (width of 4:3 picture =
27.5" )

So 42" fits the bill fine.

Archived from groups: alt.video.digital-tv (More info?)

On 21 Feb 2005 23:16:23 -0800, Brian Cantin <bcantin@cox.net> wrote:

>"me" <me@here.com> writes:
>
>> Hi,does anyone know what size 16:9 TV i would have to get, that when in 4:3
>> mode would give a 32 inch picture ? (IE,with black borders at the sides)
>> I worked it out to be about 42" but i'm not sure of the exact formula.
>> I may get a 16:9 TV soon to replace my current 32" 4:3 set,and i want to get
>> one big enough so that when watching 4:3 programmes,it isnt any smaller than
>> the 32" i have now.
>> Hope that question makes sense.!!! If anyone can answer that i would
>> appreciate it.
>>
>> thanks
>>
>>
>
>What you are requesting is an identical ratio, i.e.,
>
>16/9 X
> - = -
>4/3 32
>
>X = 32 * 16/9
> -
> 4/3
>
>X = 42.58

No, that formula only works for the width of a 16:9 set, ie. it's 16/9
÷ 4/3 = 1.33333 times wider.

For the diagonal, the formula is

sqrt( (16/9)² + 1) X
- = -
sqrt( (4/3)² + 1) 32

X = 32 * sqrt( (16/9)² + 1)
-
sqrt( (4/3)² + 1)

X = 39.16 inches

Go for the 42" anyway :-)

Charlie

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Archived from groups: alt.video.digital-tv,alt.video.fullscreen,alt.video.tv-sets,rec.arts.video.production (More info?)

"me" <me@here.com> wrote in message news:U7xSd.991$755.467@lakeread05...
> Hi,does anyone know what size 16:9 TV i would have to get, that when in
> 4:3
> mode would give a 32 inch picture ? (IE,with black borders at the sides)
> I worked it out to be about 42" but i'm not sure of the exact formula.
> I may get a 16:9 TV soon to replace my current 32" 4:3 set,and i want to
> get
> one big enough so that when watching 4:3 programmes,it isnt any smaller
> than
> the 32" i have now.
> Hope that question makes sense.!!! If anyone can answer that i would
> appreciate it.
>
> thanks
>
>

Posted this on 22/2/05, but it did not appear!?!?


32" @ 4:3 " Diag 32"; width 25.6"; height 19.2"

42" @ 16:9 Diag 42"; width 36.6"; height 20.6" (width of 4:3 picture =
27.5" )

So 42" fits the bill fine.

Archived from groups: alt.video.digital-tv (More info?)

"D. Stussy" <kd6lvw@bde-arc.ampr.org> wrote in message
newsine.LNX.4.61.0502281030310.95@kd6lvw.ampr.org...
> On Tue, 22 Feb 2005, Charlie Pearce wrote:
>> On Mon, 21 Feb 2005 18:53:23 -0800, "me" <me@here.com> wrote:
>> >Hi,does anyone know what size 16:9 TV i would have to get, that when in
>> >4:3
>> >mode would give a 32 inch picture ? (IE,with black borders at the sides)
>> >I worked it out to be about 42" but i'm not sure of the exact formula.
>> >I may get a 16:9 TV soon to replace my current 32" 4:3 set,and i want to
>> >get
>> >one big enough so that when watching 4:3 programmes,it isnt any smaller
>> >than
>> >the 32" i have now.
>> >Hope that question makes sense.!!! If anyone can answer that i would
>> >appreciate it.
>>
>> Well, according to Mr. Pythagoras, a 32 inch 4:3 rectangle has a
>> height of 19.2 inches, and a 16:9 rectangle with a height of 19.2
>> inches has a diagonal of, er...
>>
>> sqrt ( 19.2² + (19.2 x 16/9)²) = 39.16 inches.
>
> That's what I got also. At 39", you're losing only 0.4% of the picture.
> At
> 40", you're seeing 2.1% more picture.


Posted this on 22/2/05 & 23/2/05, but it did not appear!?!?

32" @ 4:3 " Diag 32"; width 25.6"; height 19.2"

42" @ 16:9 Diag 42"; width 36.6"; height 20.6" (width of 4:3 picture =
27.5" )

So 42" fits the bill fine.



>
> One should note that for a 4:3 ratio picture, the diagonal will be 5.
> For a 16:9 ratio picture, the diagonal is about 18.357.
> A 16:9 picture is 1/3rd wider than its 4:3 counterpart of the SAME height.
>
> The answers that came up with 42" are wrong because those answers also
> expanded the height by an additional 1/3rd. They will produce a LARGER
> 4:3
> picture.

Only very slightly about 1.4" or a few percent!