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Archived from groups: alt.games.whitewolf (More info?)
With the recent news that the WOD2 system will have a single
fixed TN, will only require 1 success to succeed on any roll,
and will modulate difficulty by changing the size of the dice
pool, people have been wondering how this will work out.
Since the mathematics of this aren't too difficult, I have
made a spreadsheet to figure out the results for TNs ranging
from 2 to 10 (we don't know what the fixed TN will be), and
have decided to share it with the group.
The basic equation for this is that the chance of failing
all die rolls is p=f^d, where p is the probability of
failing all rolls, f is the probability of failing a single
roll (equal to the TN minus one, divided by ten), and d
is the number of dice.
Here's the chart, the numbers on the top are the number of
dice, on the left are the TNs, the intersections show the
probability of failing on all rolls, expressed to the
nearest percent:
1 2 3 4 5 6 7 8 9 10
2 10% 1% 0% 0% 0% 0% 0% 0% 0% 0%
3 20% 4% 1% 0% 0% 0% 0% 0% 0% 0%
4 30% 9% 3% 1% 0% 0% 0% 0% 0% 0%
5 40% 16% 6% 3% 1% 0% 0% 0% 0% 0%
6 50% 25% 12% 6% 3% 2% 1% 0% 0% 0%
7 60% 36% 22% 13% 8% 5% 3% 2% 1% 1%
8 70% 49% 34% 24% 17% 12% 8% 6% 4% 03%
9 80% 64% 51% 41% 33% 26% 21% 17% 13% 11%
10 90% 81% 73% 66% 59% 53% 48% 43% 39% 35%
Frankly, it doesn't look good. Whatever the TN, it will only
distinguish broad levels of improbability, while delineating
precise increments of almost certain probability, but I suspect
that's somewhat intrinsic to dice pool systems. If the TN is
set at 8 or 9, the probabilities will cover a fairly decent
range, but one have a longer, and better modulated, range using
a stat+skill+1d10 vs TN mechanic (but of course, that wouldn't
be Storyteller). With a TN of ten, things spread out way to
far, and one would need to have vast arrays of dice to represent
almost certain success (22 dice to get less than a 10% chance
of failure).
One could tighten up these probabilities by reintroducing some
varient of the "ones cancel successes" botch mechanic, but don't
ask me for the numbers on that.
HTH
Old Toby
Least Known Dog on the Net
With the recent news that the WOD2 system will have a single
fixed TN, will only require 1 success to succeed on any roll,
and will modulate difficulty by changing the size of the dice
pool, people have been wondering how this will work out.
Since the mathematics of this aren't too difficult, I have
made a spreadsheet to figure out the results for TNs ranging
from 2 to 10 (we don't know what the fixed TN will be), and
have decided to share it with the group.
The basic equation for this is that the chance of failing
all die rolls is p=f^d, where p is the probability of
failing all rolls, f is the probability of failing a single
roll (equal to the TN minus one, divided by ten), and d
is the number of dice.
Here's the chart, the numbers on the top are the number of
dice, on the left are the TNs, the intersections show the
probability of failing on all rolls, expressed to the
nearest percent:
1 2 3 4 5 6 7 8 9 10
2 10% 1% 0% 0% 0% 0% 0% 0% 0% 0%
3 20% 4% 1% 0% 0% 0% 0% 0% 0% 0%
4 30% 9% 3% 1% 0% 0% 0% 0% 0% 0%
5 40% 16% 6% 3% 1% 0% 0% 0% 0% 0%
6 50% 25% 12% 6% 3% 2% 1% 0% 0% 0%
7 60% 36% 22% 13% 8% 5% 3% 2% 1% 1%
8 70% 49% 34% 24% 17% 12% 8% 6% 4% 03%
9 80% 64% 51% 41% 33% 26% 21% 17% 13% 11%
10 90% 81% 73% 66% 59% 53% 48% 43% 39% 35%
Frankly, it doesn't look good. Whatever the TN, it will only
distinguish broad levels of improbability, while delineating
precise increments of almost certain probability, but I suspect
that's somewhat intrinsic to dice pool systems. If the TN is
set at 8 or 9, the probabilities will cover a fairly decent
range, but one have a longer, and better modulated, range using
a stat+skill+1d10 vs TN mechanic (but of course, that wouldn't
be Storyteller). With a TN of ten, things spread out way to
far, and one would need to have vast arrays of dice to represent
almost certain success (22 dice to get less than a 10% chance
of failure).
One could tighten up these probabilities by reintroducing some
varient of the "ones cancel successes" botch mechanic, but don't
ask me for the numbers on that.
HTH
Old Toby
Least Known Dog on the Net