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192.168.1.0/22

Last response: in Networking
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October 22, 2012 2:03:41 PM

How many subnets in 192.168.1.0/22 and why? I am getting confused about what is the number of borrowed bits. Please explain

Thanking in anticipation

More about : 192 168

Anonymous
October 22, 2012 5:20:02 PM

1 network with 1022 host addresses

192.168.0.1 > 192.168.3.254


Normally 192.168.1.0 would be masked 255.255.255.0 but you have taken 2 bits from the last mask octet making 255.255.252.0 leaving the last 2 bits to be assigned to hosts.
October 22, 2012 6:18:32 PM

then here how many subnets? 1 subnet (192.168.0.1-192.168.3.254) or 3 subnets? thanks for ur response
Anonymous
October 23, 2012 12:48:10 AM


[------subnet mask /22-----][-----Host-----]
1111111.1111111.11111100.00000000

October 23, 2012 2:11:06 AM

Quote:
[------subnet mask /22-----][-----Host-----]
1111111.1111111.11111100.00000000

how many subnets here? thanks
October 23, 2012 4:13:17 PM

Homework?

In CIDR notation, /22 = 11111111.11111111.11111100.00000000 so you have 10 host bits, i.e. can have 1024 total hosts (but the gateway and broadcast come out of that so 1022 useable) on one supernet with addresses from 192.168.0.0 - 192.168.3.255.

You are using a major class C address, which has a default mask of 255.255.255.0 which is /24 (i.e. 24 network bits and 8 host bits). You borrowed two bits from the network portion, hence /22, to increase the host number from 2^8 to 2^10.
October 24, 2012 5:19:14 AM

thanks for ur response......
!