Archived from groups: rec.audio.pro (
More info?)
mrivers@d-and-d.com (Mike Rivers) writes:
>In article <115855eslb9u617@corp.supernews.com> franks.pacifier.com@pacifier.net writes:
>> Each of the stereo pgm outs of the master module of my Soundcraft Delta
>> 200 have a 1k trim pot across the active balanced output stages (in series
>> with a 1k resistor on each leg). The wiper is tied to ground.
>LIke this?:
Not exaclty, the "leg" 1Ks are right off the pot, not in series with the
output.
I've modified the drawing:
> |\ IC1A
>-------| --------------------+------------->
> |/ |
> /\/ 1K
> I
> 1K I<---+ gnd
> I
/\/ 1K
> |\ |
>-------| --------------------+------------->
> |/ IC1B
>> I am rechipping and recapping and assume these trims should be tweaked
>> once the new parts are in.
>Not necessarily. I suspect that it's to even out the difference
>between the 1K resistors. Unless you're replacing them (or any other
>gain-determining components) you probably don't need to tweak this.
Does the move of the 1Ks to the trimmer "legs" change that supposition?
My thought was that if the driver op amps weren't pretty close this pot
would need to be tweaked when changing those amps. Then again, given that
the two amps are in the same package, I'd *hope* they'd be rather
well-matched. <g> My first go-around is using BB OPA2134s
>> I'm thinking I could Y
>> the + and - legs of the output together, feed a signal through (a sweep,
>> perhaps?), and tweak the pot for maximum cancellation (scope or perhaps
>> even by ear at high gain).
>That would probably work. I don't guess the output would mind being
>shorted since it's protected by those 1K resistors. The real deal for
Good point; as you can see above, the outputs would be shorted together
in the "Y" approach, though I have some 910 ohm 0.1% Holcos I could use to
protect the outputs and be assured of a pretty close match in the test
jig.
>a balanced output is that both sides have the same impedance to
>ground. A better test would be to actually measure the impedance of
>each leg by measuring the voltage drop when you connect a known load
>resistor to each side of the output. That way even if the voltages
>aren't equal on both sides (which isn't a requirement for a balanced
>output) you can trim the source impedance.
Ah. Interesting point.
>But you can probably just leave it where it is.
That would be nice, as I have to have the L/R master boards dismounted
from the module frame and laying out of the console to get to the timmers,
which means I need a bench connector for this beast, which I haven't had
time to build yet. One more thing on that (long) do list...
Thanks, Mike, for your advice.
Frank Stearns
Mobile Audio
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