Tom's Hardware: Topic how to make cable with attenuation?
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Archived from groups: rec.audio.pro (More info?)
We are working on a project where we connect an audio card output to the
input of the card.
We are simply using a 10k and a 100k resistor to make a voltage divider.
If You want it to be exactly 20dB You will have a problem with the input and
output impedances of the system, but thats not really a problem in our
application.
By the way. How have You determined that it needs to be attenuated by 20dB ?
/Jakob
"Vedran" <vedran.vau@gmail.com> skrev i en meddelelse
news
61hrd$o9v$1@ikar.hrt.hr...
> Can somene tell me how to make cable with 20db attenuation?
> Have to connect line balanced output to mic input of some portable
reporter
> boxes.
> thank you
> Vedran
>
>
Archived from groups: rec.audio.pro (More info?)
"Vedran" <vedran.vau@gmail.com> wrote in message
news61hrd$o9v$1@ikar.hrt.hr...
> Can somene tell me how to make cable with 20db attenuation?
> Have to connect line balanced output to mic input of some portable
> reporter
> boxes.
Don't you need more than 20 dB attenuation to get line to mic level? You
say boxes, plural. If there is more than one box that would change how you
design it.
For one box you can make a simple voltage diver by putting a resistor in
series with the hot and then one across the minus and take the output across
the parallel resistor. The series resistor will be higher in value than the
parallel one. You should be able to find the values online for whatever
attenuation you need. If you want to split this to several devices, you
should also put an additional resistor on each plus and minus leg feeding
the boxes, such that the sum of all the "build out" resistors equals the
total input impedance.
Julian
OUT (high level) IN (low level)
hot -------X X X--------- hot
X
X
minus -------------X--------- minus
ground------------------------ground
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