My math tells me a 300W lamp (120v) would only pull 3W on a 12v line, if I used it as a load. Is that true? I thought it would pull a 30W load until I did the math!
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So you are correct, when put on 12v, the current will drop likewise 10 times. Power consumption goes down with the square of that. However, if you want the same amount of light produced by your lamp, you need to increase the current tenfold.
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I see that, so anyway I was just planning to use a room lamp as a 12v load (forget the light, it's just a resistor to me), but it looks like that's not going to provide much of a load at all.
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Series or parallel circuit and only the one +12 volt power supply ?
You say your lamp is a resistor and not a bulb so your voltage drop will remain constant but will only draw as much power or voltage drop as the amount of heat it can dissipate. An actual 12 volt bulb would use the current differently. If you have 2 power supply's you will have to remove one of them and do the math on the circuit for one then calculate the difference for the 2nd power supply.
In any even you have this circuit.
V ? = Ir * R or V = A * Ohms
The resistance can be found if the current and voltage are known. The current through a resistance is divided into the voltage across the resistance to find the value of the resistance. E/I/R E = I/R or R = E/I
Applied Source Voltage
I = E/R = E * (1/R) = E*G
Ohms = V over A.
So your circuit will be R= ER over 1R depending on your applied source.
Basic power formula is P = E2 over R and P = I2 * R
Or a proper hint would be an AC or DC power supply can deliver a maximum of 3A of current at 24 V so the maximum available power is 3A * 24V or 72 Watts of Power. Caution you could overheat this one unless you don't fuse it So much for your resistor.
In short dude available power is determined by using the PIE power formula. P = I * E
Keep your exponents simple and the circuit as series until you figure out the formulas or can remember them.
You never learn do you. Besides any person I know accept for us are sane in the head and in bed.
So you do not in fact live anywhere near me. Besides your sig says you are an American boy. That doesent make you a bad person just handicapped.
However I can guess you are going to post that you are not retarded either. I just hope you can spell it again since you keep making that claim from time to time.
We are all watching the Election debates.....those are the 2 you are going to vote on as president ?
The best of the best EH...Well we do feel sorry for you all. For all of us world wide.
Of course our Canadian Submariners could have used as much luck as Bush gets the other day...........In either case a smoking hole will be left to debate on.
Question for you soddy WHEN THE [-peep-] DID GOD START LOVEING CANADA??? Cause I sure missed that ride.
Just a reminder Canada is a country going no where if god loved it I would be running it.
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Simplifying calculations... A 300W bulb for 120V AC current has a resistance of 48 Ohms. Connected to a 12 V DC source, it will be a load of 3 W. This is because power P = V^2/R, where V is the voltage drop across the load.
Don't listen to SoD. He just aims to confuse.
AC power is usually a little more complex than P = VI, but working with just resistances simplifies it greatly.
I'm a 4th year electrical engineering student, so although I don't know everything I'm sure I could help you with most of your questions.
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I'm sorry, sir. I retract my statements and pledge my allegiance to SoD.
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"There's more to life than profits."
<font color=red>"Like what?"</font color=red>
"Like, you know, Slurpees and stuff."
<A HREF="http://images.southparkstudios.com/media/video/707/slurpees.mov" target="_new">South Park</A>
Well, Beavis says the angle of the dangle is inversely proportional to the heat of the beat. So there!
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Hehe, I actually figured out that P=V^2/R when I was using the other two equations. It's been a while since my physics classes!
But it's nice to speak with a fellow human!
<font color=blue>Only a place as big as the internet could be home to a hero as big as Crashman!</font color=blue>
<font color=red>Only a place as big as the internet could be home to an ego as large as Crashman's!</font color=red>
ksoth has an 8th grade education? He should become an engineer while he still knows everything!
<font color=blue>Only a place as big as the internet could be home to a hero as big as Crashman!</font color=blue>
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