For the math experts (random draw of decks)
Anonymous
Archived from groups: rec.games.tradingcards.jyhad (More info?)
For the math experts out there, I'd like to ask some help and advice
on this.
I've tested a simple method of deck distribution last year during a
sealed deck tournament and it went quite well (9 players), but I lack
the math skills to calculate the real difference in probabilities. I
thought it would be good to add some choices to players and therefore
diminishing the chances of everybody not being really satisfied with
the deck they get during this type of event, and thought it would be
good to our prerelease events (delayed for one week due to customs
problems).
Basically, the organizer asks for each player to prioritize their
choices given the decks available. So, let's say, I'd like to get the
Baali deck, Alastor second, !Gangrel third.
The organizer polls the results and see which decks had too much
demand based solely on the players' first options. If he has the
available number to give one type of deck or another to all that chose
it as first option, he does it. Say that he has 4 copies of each deck
available and only 2 players chose Alastors. They get that deck.
Conversely, say that 6 players chose Baali. The organizer uses some
random method to assing the 4 copies available between these players.
The two unlucky ones don't get the Baali deck (say I am one of these
two).
Now the organizer compares which players are left with no deck and
which copies are still available. He repeats the process using any
player's second option. In our example there are still 2 Alastors. Say
that me and two other players chose Alastor as second option. We enter
a new round of random assignment. This time I'm in and get the Alastor
deck. The third player is left to a new round based on third options,
and so on, until everyone gets one deck to play.
I assume this method greatly reduces the chance of everyone getting a
third or fourth option, and at least introduces the notion that if one
gets a deck they'd not normally choose, they have to be out of luck in
two or three drawings instead of just one. But besides these pratical
conotations, I'd like to know if I'm right regarding math.
I suspect that a single, simple drawing means that *all* players could
potentially get what would be otherwise third and fourth options, even
if some chose decks that are not all too popular in their metagames,
while the method I've used last year guarantees that at least some get
their first option and maximize the chances to make (almost) everyone
get their first or second options. I suspect that in my city most will
choose Alastor, per example, so a single drawing could frustrate
people who choose Baali or Anathema, even if not that many players
want these and there are plenty of copies to satisfy them. Could
someone calculate the probabilities to confirm if my suspicions are
correct?
best,
Fabio "Sooner" Macedo
V:TES National Coordinator for Brazil
Giovanni Newsletter Editor

V:tES Brasil Site (only in Portuguese for now)
http://planeta.terra.com.br/lazer/vtesbrasil/
For the math experts out there, I'd like to ask some help and advice
on this.
I've tested a simple method of deck distribution last year during a
sealed deck tournament and it went quite well (9 players), but I lack
the math skills to calculate the real difference in probabilities. I
thought it would be good to add some choices to players and therefore
diminishing the chances of everybody not being really satisfied with
the deck they get during this type of event, and thought it would be
good to our prerelease events (delayed for one week due to customs
problems).
Basically, the organizer asks for each player to prioritize their
choices given the decks available. So, let's say, I'd like to get the
Baali deck, Alastor second, !Gangrel third.
The organizer polls the results and see which decks had too much
demand based solely on the players' first options. If he has the
available number to give one type of deck or another to all that chose
it as first option, he does it. Say that he has 4 copies of each deck
available and only 2 players chose Alastors. They get that deck.
Conversely, say that 6 players chose Baali. The organizer uses some
random method to assing the 4 copies available between these players.
The two unlucky ones don't get the Baali deck (say I am one of these
two).
Now the organizer compares which players are left with no deck and
which copies are still available. He repeats the process using any
player's second option. In our example there are still 2 Alastors. Say
that me and two other players chose Alastor as second option. We enter
a new round of random assignment. This time I'm in and get the Alastor
deck. The third player is left to a new round based on third options,
and so on, until everyone gets one deck to play.
I assume this method greatly reduces the chance of everyone getting a
third or fourth option, and at least introduces the notion that if one
gets a deck they'd not normally choose, they have to be out of luck in
two or three drawings instead of just one. But besides these pratical
conotations, I'd like to know if I'm right regarding math.
I suspect that a single, simple drawing means that *all* players could
potentially get what would be otherwise third and fourth options, even
if some chose decks that are not all too popular in their metagames,
while the method I've used last year guarantees that at least some get
their first option and maximize the chances to make (almost) everyone
get their first or second options. I suspect that in my city most will
choose Alastor, per example, so a single drawing could frustrate
people who choose Baali or Anathema, even if not that many players
want these and there are plenty of copies to satisfy them. Could
someone calculate the probabilities to confirm if my suspicions are
correct?
best,
Fabio "Sooner" Macedo
V:TES National Coordinator for Brazil
Giovanni Newsletter Editor

V:tES Brasil Site (only in Portuguese for now)
http://planeta.terra.com.br/lazer/vtesbrasil/
8
answers
Last reply
More about math experts random draw decks

Archived from groups: rec.games.tradingcards.jyhad (More info?)
Fabio "Sooner" Macedo wrote:
> I suspect that a single, simple drawing means that *all* players could
> potentially get what would be otherwise third and fourth options, even
> if some chose decks that are not all too popular in their metagames,
> while the method I've used last year guarantees that at least some get
> their first option and maximize the chances to make (almost) everyone
> get their first or second options. I suspect that in my city most will
> choose Alastor, per example, so a single drawing could frustrate
> people who choose Baali or Anathema, even if not that many players
> want these and there are plenty of copies to satisfy them. Could
> someone calculate the probabilities to confirm if my suspicions are
> correct?
(I assume by "simple drawing" people draw numbers, and then pick a
remaining deck in order of number drawn.)
Under your method, at least as many, and probably more, people will get
their first pick (exact probabilities depend on how many people want
each starter, of course). Conversely, less people will get their second
or third pick. So you'll have more people who have their first pick,
and more people who have their fourth pick.
Whether this is preferable or not is up to you. It punishes people who
pick the most popular starter, and rewards the people who pick the
second or third most popular starter. People who pick the least popular
starter are unaffected  there will never be a situation where they
won't be able to get it.
Colin McGuigan 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
Fabio "Sooner" Macedo wrote:
> I suspect that a single, simple drawing means that *all* players could
> potentially get what would be otherwise third and fourth options, even
> if some chose decks that are not all too popular in their metagames,
> while the method I've used last year guarantees that at least some get
> their first option and maximize the chances to make (almost) everyone
> get their first or second options. I suspect that in my city most will
> choose Alastor, per example, so a single drawing could frustrate
> people who choose Baali or Anathema, even if not that many players
> want these and there are plenty of copies to satisfy them. Could
> someone calculate the probabilities to confirm if my suspicions are
> correct?
(I assume by "simple drawing" people draw numbers, and then pick a
remaining deck in order of number drawn.)
Under your method, at least as many, and probably more, people will get
their first pick (exact probabilities depend on how many people want
each starter, of course). Conversely, less people will get their second
or third pick. So you'll have more people who have their first pick,
and more people who have their fourth pick.
Whether this is preferable or not is up to you. It punishes people who
pick the most popular starter, and rewards the people who pick the
second or third most popular starter. People who pick the least popular
starter are unaffected  there will never be a situation where they
won't be able to get it.
Colin McGuigan 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
> I've tested a simple method of deck distribution last year during a
> sealed deck tournament and it went quite well (9 players), but I lack
> the math skills to calculate the real difference in probabilities.
There are a few too many permutations to consider to get paydata, I'd
suggest giving the problem to a college student to do an Independent Study
Project on.
> The organizer polls the results and see which decks had too much
> demand based solely on the players' first options. If he has the
> available number to give one type of deck or another to all that chose
> it as first option, he does it. Say that he has 4 copies of each deck
> available and only 2 players chose Alastors. They get that deck.
>
I like your idea, good luck with it.
> Conversely, say that 6 players chose Baali. The organizer uses some
> random method to assing the 4 copies available between these players.
> The two unlucky ones don't get the Baali deck (say I am one of these
> two).
>
I'd actually offer to give people their second choices before using a
random system. People with unpopular second choices can get their second
choice and be relatively happy. Then, if the First Choice deck is still
too much in demand, you roll off.
> I assume this method greatly reduces the chance of everyone getting a
> third or fourth option
It does, but at some cost. Let's say we have 6 (AN)  6 (B)  2 (G)  2
(AL). Worst case scenario is someone lists Baali and Anathema as their top
2. He has a 2/3 chance of getting his top choice  versus 1/4  but a 0
chance of getting his second choice  versus 1/4.
If the numbers are 6 (B)  4 (AN)  4 (G)  2 (AL), the two players who
miss out on Baali get Alastors, regardless of where it lies in their
priorities.
> I suspect that a single, simple drawing means that *all* players could
> potentially get what would be otherwise third and fourth options
That's why all of the sealed play I've seen allowed you to trade your
deck. An even number of each deck is drawn for the group, and everyone
gets assigned a random starter, allowed to trade before opening it. Even
if you do implement your system, I'd still give people the chance to trade
decks, on the off chance that Person A's Third Choice is more personally
satisfying than Person B's Second Choice. 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
LSJ wrote:
> You might try adapting one of the methods for assigning
> powers in Diplomacy, since quite a lot of noses have been
> poked into that bag.
>
> (In fact, it sounds like the method you adopted was
> a parallel to method 2A here
> http://www.diplom.org/Zine/F1998M/Tarzan/assign.html
> )
>
> It seems that method 2C is the fairest, but then
> you also have to come up with an accurate
> "satisfaction" weighting.
> It's also the most complicated to compute, IMO.
Or, you could simply debate which satisfaction table best suits your
group among the seven players. Meta meta meta.
Jeff 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
You might try adapting one of the methods for assigning
powers in Diplomacy, since quite a lot of noses have been
poked into that bag.
(In fact, it sounds like the method you adopted was
a parallel to method 2A here
http://www.diplom.org/Zine/F1998M/Tarzan/assign.html
)
It seems that method 2C is the fairest, but then
you also have to come up with an accurate
"satisfaction" weighting.
It's also the most complicated to compute, IMO.

LSJ (vtesrep@whitewolf.com) V:TES Net.Rep for White Wolf, Inc.
V:TES homepage: http://www.whitewolf.com/vtes/
Though effective, appear to be ineffective  Sun Tzu 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
On Tue, 22 Feb 2005 14:17:16 0500, Gregory Stuart Pettigrew
<etherial@sidehack.sat.gweep.net> wrote:
>> Conversely, say that 6 players chose Baali. The organizer uses some
>> random method to assing the 4 copies available between these players.
>> The two unlucky ones don't get the Baali deck (say I am one of these
>> two).
>>
>
>I'd actually offer to give people their second choices before using a
>random system. People with unpopular second choices can get their second
>choice and be relatively happy. Then, if the First Choice deck is still
>too much in demand, you roll off.
That's a good advice. I didn't take into consideration that now we get
4 choices (I tried it with Anarchs decks, only 3 choices for 9 people.
Maybe this changes probabilities, I really don't know).
>It does, but at some cost. Let's say we have 6 (AN)  6 (B)  2 (G)  2
>(AL). Worst case scenario is someone lists Baali and Anathema as their top
>2. He has a 2/3 chance of getting his top choice  versus 1/4  but a 0
>chance of getting his second choice  versus 1/4.
>If the numbers are 6 (B)  4 (AN)  4 (G)  2 (AL), the two players who
>miss out on Baali get Alastors, regardless of where it lies in their
>priorities.
Oh yeah, I didn't think of that. But I see some point in checking in
with other players to know the risks of going for the most popular
option. It becomes a "no pain, no gain" situation. I like that, seems
like gambling without the dreadful conotations of it.
>> I suspect that a single, simple drawing means that *all* players could
>> potentially get what would be otherwise third and fourth options
>
>That's why all of the sealed play I've seen allowed you to trade your
>deck. An even number of each deck is drawn for the group, and everyone
>gets assigned a random starter, allowed to trade before opening it. Even
>if you do implement your system, I'd still give people the chance to trade
>decks, on the off chance that Person A's Third Choice is more personally
>satisfying than Person B's Second Choice.
It will be allowed, of course. Just forgot to mention it, sorry.
Many thanks for your insights!
best,
Fabio "Sooner" Macedo
V:TES National Coordinator for Brazil
Giovanni Clan Newsletter Editor

V:tES Brasil Site (only in Portuguese for now)
http://planeta.terra.com.br/lazer/vtesbrasil/ 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
On Tue, 22 Feb 2005 14:17:16 0500, Gregory Stuart Pettigrew
<etherial@sidehack.sat.gweep.net> wrote:
>> I assume this method greatly reduces the chance of everyone getting a
>> third or fourth option
>
> It does, but at some cost. Let's say we have 6 (AN)  6 (B)  2 (G)  2
> (AL). Worst case scenario is someone lists Baali and Anathema as their
> top
> 2. He has a 2/3 chance of getting his top choice  versus 1/4  but a 0
> chance of getting his second choice  versus 1/4.
>
> If the numbers are 6 (B)  4 (AN)  4 (G)  2 (AL), the two players who
> miss out on Baali get Alastors, regardless of where it lies in their
> priorities.
You could assign the Alastors to those aspiring Baali players who had
Alastors highest up. Like, if two have it second, the problem is solved.
I made a sumutility matrix (that was loosely based on the transportation
model) that aims to maximize the total combined utility of all players
participating. From that apporach, giving the most possible number of
players their first picks is the best solution (because in the majority
of cases the majority of players will get their first pick). Shuffling
with deviancefromgroupaverageutility is a poor choice, given how few
options there are (If your options are assigning 12 first picks, 2 second
and 2 third picks, or to assign 10 first picks and 6 second picks, it is
probably better to go with the former  that way, 3 out of 4 players get
their first picks).

Bye,
Daneel 
Archived from groups: rec.games.tradingcards.jyhad (More info?)
On Tue, 22 Feb 2005 15:56:53 0500, "LSJ"
<vtesrepSPAM@TRAPwhitewolf.com> wrote:
>You might try adapting one of the methods for assigning
>powers in Diplomacy, since quite a lot of noses have been
>poked into that bag.
>(In fact, it sounds like the method you adopted was
>a parallel to method 2A here
>http://www.diplom.org/Zine/F1998M/Tarzan/assign.html
>It seems that method 2C is the fairest, but then
>you also have to come up with an accurate
>"satisfaction" weighting.
>It's also the most complicated to compute, IMO.
Thanks! For the sake of brevity (and lack of an available PC/laptop at
the event) I'll leave 2C aside, though I find it's a pity since it
seems really the best method. I'm considering 2B.
best,
Fabio "Sooner" Macedo
V:TES National Coordinator for Brazil
Giovanni Newsletter Editor

V:tES Brasil Site (only in Portuguese for now)
http://planeta.terra.com.br/lazer/vtesbrasil/
Related Resources
Ask a new question
Read More
Video Games
Related Resources
 Ultralight Distribution
 Fire or lightning trapsin?
 GDC 2006: Digital Distribution Powers Up
 [Case Study] Small Tournament structure
 Beginner's Decks
 Where are the Mata Hari decks?
 Ubisoft Launches Uplay PC Distribution & Social Platform
 Which Linux distribution do you recommend I try?
 Starheat distribution
 ERRATE PTO !!! ;)
 MS sign deal with Exent for digital game distribution