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Grab a Radeon RX 5700 Card for Just $279

Visiontek AMD Radeon RX 5700
(Image credit: Rakuten)

The Radeon RX 5700 is the best graphics card for 2K gaming, thanks to its great combination of high frame rates and reasonable pricing. The cards typically start at around $350, though we've seen some models drop as low as $290 this holiday season.

However, today, Rakuten is selling a Visiontek-brand Radeon RX 5700 card for just $279, the lowest price around. This card follows the reference design so it has a single fan and the classic silver casing we saw on the original cards that launched in August.

Visiontek Radeon RX 5700: was $334 now $279 @Rakuten
The best card for 2K gaming, the Radeon RX 5700 sports a base clock speed of 1,465 MHz and a boost clock of 1,725 MHz, along with 8GB of GDDR6 RAM.View Deal

In our tests, a stock RX 5700 card like this one got 11% higher frame rates than an Nvidia RTX 2060.  The RX 5700 requires about 180 watts of power, which makes it acceptable to use with a 600 or 650-watt power supply. 

Because this card is the stock design, it's only rated for a modest 1,725 MHz boost clock where overclocked cards can hit higher speeds. However, for this price, the ability to play 2K games at smooth settings is quite a bargain. 

If you're a frequent Rakuten shopper, you'll be pleased to know that the Visiontek RX 5700 comes with $55.80 worth of points if you buy it by the end of December 19th.

  • InvalidError
    If the 5700s keeps coming down, there won't be much room left between the 5500 and 5700 to squeeze the 5600s in next month unless the 5500 goes down some, which would be great for anyone looking for entry-level performance-per-dollar.
    Reply
  • larkspur
    This previously reported Radeon RX 570 4gb is still by far the best performance per dollar you can get: https://www.newegg.com/asrock-radeon-rx-570-rx570-4g/p/N82E16814930010?Description=rx%20570&cm_re=rx_570-_-14-930-010-_-Product
    But yeah, I do like the RX5700 at this price, down $10 from its previous low... but sold out of course! I just wonder how long the RX5500 is going to continue to be overpriced. The 1660 is destroying it right now...
    Reply
  • King_V
    A slight edge on the ASRock (which are reported to have noisy coolers)

    https://www.newegg.com/xfx-radeon-rx-570-rx-570p427d6/p/N82E16814150795
    $99.99 after $10 promo code and $20 mail-in-rebate.

    I don't know enough about this particular model to know if its cooler is quieter or more effective, though.
    Reply
  • Chung Leong
    The market is pretty efficient it seems. Despite the superlatives from various media outlets it figured out that the RX 5700 is a really a card that competes with the GTX 1660 Ti.
    Reply
  • King_V
    Chung Leong said:
    The market is pretty efficient it seems. Despite the superlatives from various media outlets it figured out that the RX 5700 is a really a card that competes with the GTX 1660 Ti.

    Care to justify that comment? Because this sounds like you're saying the RX 5700 performs on the level of the 1660Ti, and the performance data does not back that at all.
    Reply
  • Chung Leong
    King_V said:
    Care to justify that comment? Because this sounds like you're saying the RX 5700 performs on the level of the 1660Ti, and the performance data does not back that at all.

    But the RX 5700 can't do ray-tracing. The market has correctly priced it as a product in the same league as the GTX 1660 Ti.
    Reply
  • InvalidError
    Chung Leong said:
    But the RX 5700 can't do ray-tracing.
    And Crytek has demonstrated that you don't need raytracing-specific hardware to achieve raytracing-like results on older hardware, so RTX may be obsolete already.
    Reply
  • Chung Leong
    InvalidError said:
    And Crytek has demonstrated that you don't need raytracing-specific hardware to achieve raytracing-like results on older hardware, so RTX may be obsolete already.

    <Mod Edit> Twenty years ago Intel showed us that we can ray-trace a world full of shiny balls using just the CPU. Perfect reflection is not hard computationally.
    Reply