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G.Skill's Latest High Capacity DDR4 Kit Is Also Its Fastest

G.Skill announced a new high-capacity memory kit in the Trident Z product line. The new kit is also the company’s fastest high-capacity kit to date.

The 32 GB kit comes with four 8 GB DIMMs powered by Samsung IC memory chips. The RAM operates at 3866 MHz with timings of 18-19-19-39, and it pulls 1.35 V of power from the motherboard.

Although this isn’t G.Skill’s fastest RAM kit on the market, as the company has some DDR4 kits that operate at over 4000 MHz, it is G.Skill’s fastest 32 GB RAM kit.

G.Skill sent us a CPU-Z screenshot of the RAM to show that it is stable while running on a system with an Asus Z170-Deluxe motherboard and an Intel Core i7-6600K. The screenshot actually shows the RAM operating at 3867 MHz, but this is due to a slight variance in the base clock.

There is currently no word on pricing or availability.

  • greens
    18538231 said:
    G.Skill announced a new high-capacity memory kit in its Trident Z product line, which is also the company’s fastest high-capacity kit to date.

    G.Skill's Latest High Capacity DDR4 Kit Is Also Its Fastest : Read more

    Hmm
    (CL/(freq-in-MHZ) * 1000) = timing in ns
    18/3867*1000=4.65ns
    14/3200*1000=4.38ns

    I don't believe it is the fastest 32GB kit available from that manufacturer, very simplified equation but you can see that actual latency is lower on the 14CAS 3200MHZ kits. Could be wrong, but i'm pretty sure there is more to it than just pumping up the MHZ number.

    Reply
  • abbadon_34
    Nice jump from 1066 to 1934
    Reply
  • redice611
    Imaged shows it was an i5 processor used in the testing.
    Reply
  • N3xt3ch
    Minor typo - "Core i7-6600K" should be Core i5.
    Reply
  • damric
    MT/s NOT MHz.
    Reply
  • CB
    The 32 GB kit comes with four 8 GB DIMMs powered by Samsung IC memory chips. The RAM operates at 3866 MHz with timings of 18-19-19-39, and it pulls 1.35 V of power from the motherboard.

    Please please please... let's get things right.. voltage X current = power. 1.35 V of power just doesn't make sense. To state that the operational voltage is 1.35v would be correct.
    Reply